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Lithium-ion Batteries in Hybrid Vehicles: Modeling and Technical Characteristics

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Written at somewhere on the Earth

In a Fuel Cell Hybrid Electric Vehicle (FCHEV) powertrain, we know that Fuel Cells respond relatively slowly to sudden load changes. Therefore, to enable the vehicle to accelerate smoothly and recover energy during braking, we need another “companion” that can react more swiftly: the Battery.

In an FCHEV system, the Battery acts as the Energy Storage System (ESS) or an energy buffer.

This article will not delve too deeply into chemistry but will focus on the physical quantities and mathematical formulas necessary for you to build a Battery Model on a computer (e.g., using MATLAB/Simulink). 🔋

1. Structure and Principle: The “Rocking Chair”

Fundamentally, a Lithium-ion battery operates based on the movement of Lithium ions (Li+Li^+) between two electrodes. This back-and-forth movement is why it is often referred to as a “rocking chair” battery.

Structure

Working Principle

Imagine Lithium ions as commuters:

2. Core Simulation Parameters

To simulate a battery in MATLAB/Simulink, we are less concerned with detailed chemical reactions and more interested in the following macroscopic variables:

2.1. Capacity (QQ)

This represents the ability of the battery to store electric charge.

2.2. State of Charge (SOC)

This is the “fuel gauge” of the battery, indicating the percentage of energy remaining.

Calculation Formula (Coulomb Counting): To calculate SOC at time tt, we integrate the charging/discharging current over time:

SOC(t)=SOC(t0)1Qnomt0tI(t)dtSOC(t) = SOC(t_0) - \frac{1}{Q_{nom}} \int_{t_0}^{t} I(t) \, dt

Where:

2.3. Depth of Discharge (DOD)

The inverse of SOC.

DOD(t)=1SOC(t)DOD(t) = 1 - SOC(t)

2.4. Open Circuit Voltage (OCV)

This is the battery’s voltage when no current is flowing (at rest).

2.5. Internal Resistance (RR)

A battery is not an ideal voltage source; it has internal resistance.

3. Equivalent Circuit Model (ECM)

For Energy Management System (EMS) algorithms, we often use the R-int Model (the simplest Internal Resistance Model).

The terminal voltage equation (VtermV_{term}) under load is:

Vterm=Voc(SOC)IRintV_{term} = V_{oc}(SOC) - I \cdot R_{int}

Battery Power (PbattP_{batt}): Pbatt=VtermI=VocII2RintP_{batt} = V_{term} \cdot I = V_{oc} \cdot I - I^2 \cdot R_{int}

4. Case Study: Toyota Mirai Battery Pack 🚗

In the Toyota Mirai (Gen 2), the Lithium-ion battery is not used for long-range driving but rather to support acceleration and capture regenerative braking energy.

Assumed Specifications (for the High Voltage Pack):

Simulation Scenario: The car is cruising with an initial SOC of 60%. The driver accelerates hard to overtake, demanding a discharge current of I=50AI = 50 A for 10 seconds.

Calculations:

  1. SOC Drop:

    • Charge consumed: ΔQ=I×t=50×10=500 Coulombs\Delta Q = I \times t = 50 \times 10 = 500 \text{ Coulombs}.
    • Convert to Ah: 50036000.138 Ah\frac{500}{3600} \approx 0.138 \text{ Ah}.
    • Percentage lost: 0.1384.0×1003.47%\frac{0.138}{4.0} \times 100 \approx 3.47\%.
    • SOCnew=60%3.47%=56.53%\Rightarrow SOC_{new} = 60\% - 3.47\% = 56.53\%.
  2. Terminal Voltage (VtermV_{term}):

    • Assume at SOC=60%SOC=60\%, the lookup table gives Voc320VV_{oc} \approx 320V.
    • Voltage drop due to resistance: Vdrop=I×R=50×0.5=25VV_{drop} = I \times R = 50 \times 0.5 = 25V.
    • Vterm=32025=295V\Rightarrow V_{term} = 320 - 25 = 295V.
  3. Actual Power (PbattP_{batt}):

    • Pbatt=295V×50A=14,750W=14.75 kWP_{batt} = 295V \times 50A = 14,750W = 14.75 \text{ kW}.

Conclusion: In just 10 seconds of acceleration, the battery lost nearly 3.5% of its capacity, and the voltage sagged by 25V. This illustrates why the EMS must carefully coordinate power flow to avoid “shocking” or rapidly depleting the battery.


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